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The rate of reaction X to Y becomes 8 t...

The rate of reaction `X to Y ` becomes 8 times when the concentration of the reactant X is doubled. Write the rate law of the reaction.

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`Let r_1 = k [x]^n`
` r_2 = k [2X]^n , (r_2)/(r_1) = k [2 X]^(n) //k [X]^(n) = 8`
or ` 2^n = 8 or (2)^3 =8`
` therefore n=3 " " therefore ` Rate law `=k [X]^3`
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