In a first order reaction, 10% of the reactant is consumed in 25 minutes. Calculate :
The time required for completing 17% of the reaction.

Explanation

For a first order reaction,
` k= ( 2.303 )/(t) log "" (a)/((a-x))`
`=(2.303)/( t) log ""(100)/((100-10)) = 4.215 xx 10^(-3) min""^(-1)`
` t=( 2.303)/(k) log (a)/((a-x)) = ( 2.303)/(4.215 xx 10^(-3)) log "" (100)/(83)`
` = 44.21 min`