An alkyl halide with molecular formula `C_6H_13Cl` when treated with alcoholic KOH gave two isomeric alkenes, A and B. Reductive ozonolysis of the mixture gave the following compounds:
(i) `CH_3COCH_3` (ii) `CH_3CHO`
(iii) `CH_3 CH_2CHO and (CH_3)_2 CHCHO`.
Write the structural formula of alkyl halide.

Explanation

From the products of reductive ozonolysis, we see that the two pairs which can constitute six carbon atoms are :
(i) `CH_3-CO - CH_3 and CH_3 CH_2 CHO and `
(ii) `CH_3 CHO and (CH_3)_2 CH.CHO`
From these products, the two isomeric alkenes can be easily written below:

These two isomeric alkenes can be obtained by the dehydrohalogenation of alkyl halide (`C_6H_13Cl`). It is possible only, if the alkyl halide is