The following electrochemical cell is set up at 298 K:
`Zn//Zn^(2+) (aq) (1 M) || Cu^(2+) (aq) (1 M)//Cu`
Given: `E^(@)Zn^(2+)//Zn =-0.761 V, E^(@) Cu^(2+)//Cu=+0.339 V`
(1) Write the cell reaction.
(2) Calculate the emf and free energy change at 298 K

For the cell : Zn"|"Zn^(2+) (a=1)"||"Cu^(2+) (a=1)"|"Cu Given that E_(Zn//Zn^(2+))=0.761 V, E_(Cu^(2+)//Cu)=0.339V (i) Write the cell reaction. (ii) Calculate the emf and free energy change at 298 K involved in the cell. [Faraday's constant F = 96500 coulomb eq^(-1) ]

Calculate the e.m.f. of the cell Zn//Zn^(2+) (0.1M) "||" Cu^(2+) (0.01M) "|"Cu E_(Zn^(2+)//Zn)^(Theta)= -0.76 " V and "E_(Cu^(2+)//Cu)^(Theta)=0.34V

Calculate E_("cell") at 25^(@)C for the reaction : Zn+Cu^(2+) (0.20M) to Zn^(2+) (0.50M)+Cu Given E^(Theta) (Zn^(2+)//Zn)= -0.76V, E^(Theta)(Cu^(2+)//Cu)=0.34V .

Calculate the equilibrium constant for the reaction at 298 K Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s) Given " " E_(Zn^(2+)//Zn)^(@)=-0.76 V and E_(Cu^(2+)//Cu)^(@)=+0.34 V

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate E_(cell)^(0) of (at 298K) Zn(s)//ZnSO_(4)(aq)||CuSO_(4)(aq)//Cu(s) given that E_(Zn//Zn^(2+)(aq))^(0)=0.76V E_(Cu(s)//Cu^(2+)(aq))^(0)=-0.34V

For the galvanic cell: Zn(s) | Zn^(2+)(aq) (1.0 M) || Ni^(2+)(aq) (1.0 M) | Ni(s) , E_(cell)^o will be [Given E_((Zn^(2+)) /(Zn))^0 = -0.76 V , E_((Ni^(2+))/(Ni))^0= -0.25V ]

Consider the cell : Zn|Zn^(2+)(aq)(1.0M)||Cu^(2+)(aq)(1.0M)||Cu Thee standard reduction potentials are 0.350V for Cu^(2+)(aq)+2e^(-)rarrCu and -0.763V for Zn^(2+)(aq)+2e^(-) rarr Zn a. Write the cell reaction. b. Calculate the EMF of the cell. c. Is the reaction spontaneous or not ?

Write Nernst equation for the following cell reaction : Zn"|"Zn^(2+)(aq)"||"Cu^(2+)(aq)"|"Cu(s)