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The half-lives of 2 samples are 0.1 and ...

The half-lives of 2 samples are 0.1 and 0.4 seconds. Their initial conc. are 200 and 50 respectively. What is the order of the reaction ?

A

0

B

2

C

1

D

4

Text Solution

Verified by Experts

The correct Answer is:
B
`((t_(1//2))_1)/((t_(1//2))=((a_2)/(a_1))^(n-1) , ((0.1 )/(0.4)) = ((50 )/(200 ))^(n-1) ) " " or 1/4 = (1/4)^(n-1) , (1/4)^1 =(1/4)^(n-1) , 1=n-1 or n=2`
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