(i) An organic compound (P), `C_5H_10O` reacts with dil. `H_2SO_4` to give (Q) and (R). Both (Q) and (R) give positive iodoform test. The reactivity of organic compound (P) is `10^15` times more than ethylene with respect to dil. `H_2SO_4`
(i) Identify the compounds (P), (Q) and (R).
(ii) Give reason for the extraordinary reactivity of compound (P).

Explanation

To solve the problem, we need to identify the organic compounds P, Q, and R based on the given information and then explain the extraordinary reactivity of compound P.

### Step-by-Step Solution:

**Step 1: Identify Compound P**
- The molecular formula of compound P is \(C_5H_{10}O\).
- Since it reacts with dilute \(H_2SO_4\) and gives positive iodoform tests for both Q and R, compound P must contain a carbonyl group (specifically, a ketone or an aldehyde) that can lead to the formation of a methyl ketone upon reaction.
- A possible structure for P is 3-pentanone, which can be represented as:
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