An 11 years old child's score on Stanford-Binet Intelligence Scale is 130. By assuming? =100 and s = 15 in a normal probability curve, calculate the percentage of 11 years old children, this child has scored better than.

Options

A. `78%`
B. `80%`
C. `98%`
D. `88%`

Answer

C

Explanation

`Z=(x-mu)/(sigma)=Z=(130-100)/(15)`
`=2=97.7%=98%`
According to the Stanford Binet Intelligence Scale index 2 of Z refers to 97.7% which is approximately 98%.