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A cuboidal box is 13 cm long, 11 cm broa...

A cuboidal box is 13 cm long, 11 cm broad and 9 cm high. A cubical box has side 12 cm, Tanu wants to pack 3060 cubes of side 1 cm in these boxes. The number of the cubes left unpacked in these boxes is

A

30

B

45

C

15

D

28

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will calculate the volumes of the cuboidal box and the cubical box, then determine how many 1 cm³ cubes can be packed into these boxes, and finally find out how many cubes will remain unpacked. ### Step 1: Calculate the volume of the cuboidal box. The formula for the volume of a cuboid is: \[ \text{Volume} = \text{Length} \times \text{Breadth} \times \text{Height} \] Given dimensions: - Length = 13 cm - Breadth = 11 cm - Height = 9 cm Calculating the volume: \[ \text{Volume of cuboidal box} = 13 \, \text{cm} \times 11 \, \text{cm} \times 9 \, \text{cm} = 1287 \, \text{cm}^3 \] ### Step 2: Calculate the volume of the cubical box. The formula for the volume of a cube is: \[ \text{Volume} = \text{Side}^3 \] Given side: - Side = 12 cm Calculating the volume: \[ \text{Volume of cubical box} = 12 \, \text{cm} \times 12 \, \text{cm} \times 12 \, \text{cm} = 1728 \, \text{cm}^3 \] ### Step 3: Calculate the total volume available for packing. Now, we add the volumes of both boxes: \[ \text{Total volume} = \text{Volume of cuboidal box} + \text{Volume of cubical box} \] Calculating the total volume: \[ \text{Total volume} = 1287 \, \text{cm}^3 + 1728 \, \text{cm}^3 = 3015 \, \text{cm}^3 \] ### Step 4: Calculate the total volume of the small cubes. Each small cube has a side of 1 cm, so its volume is: \[ \text{Volume of small cube} = 1 \, \text{cm}^3 \] Given that Tanu wants to pack 3060 small cubes, the total volume of these cubes is: \[ \text{Total volume of small cubes} = 3060 \, \text{cubes} \times 1 \, \text{cm}^3 = 3060 \, \text{cm}^3 \] ### Step 5: Calculate how many cubes can be packed. Now, we find out how many cubes can actually be packed in the total volume available: \[ \text{Cubes packed} = \frac{\text{Total volume}}{\text{Volume of small cube}} = \frac{3015 \, \text{cm}^3}{1 \, \text{cm}^3} = 3015 \, \text{cubes} \] ### Step 6: Calculate the number of unpacked cubes. Finally, we find the number of unpacked cubes: \[ \text{Unpacked cubes} = \text{Total cubes} - \text{Cubes packed} = 3060 - 3015 = 45 \] ### Final Answer: The number of cubes left unpacked in these boxes is **45**. ---
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