If monthly salary of A is 20% more than the salary of B. Salary of B is 30% salary of C. if their total salary per month is Rs. 74700, then the salary of C is

Options

A. Rs, 50000
B. Rs. 45000
C. Rs. 25000
D. Rs. 35000

Answer

To solve the problem step by step, we will denote the salaries of A, B, and C as follows:

Let:
- Salary of B = B
- Salary of C = C
- Salary of A = A

### Step 1: Establish the relationship between A and B
According to the problem, the salary of A is 20% more than the salary of B. This can be expressed mathematically as:
\[ A = B + 0.2B = 1.2B \]

### Step 2: Establish the relationship between B and C
The problem states that the salary of B is 30% of the salary of C. This can be expressed as:
\[ B = 0.3C \]

### Step 3: Substitute B in the equation for A
Now, we can substitute the value of B from Step 2 into the equation for A:
\[ A = 1.2B = 1.2(0.3C) = 0.36C \]

### Step 4: Express total salary in terms of C
The total salary of A, B, and C is given as Rs. 74,700. Therefore, we can write:
\[ A + B + C = 74700 \]
Substituting the expressions for A and B in terms of C:
\[ 0.36C + 0.3C + C = 74700 \]

### Step 5: Combine like terms
Combining the terms on the left side:
\[ (0.36C + 0.3C + 1C) = 74700 \]
\[ 1.66C = 74700 \]

### Step 6: Solve for C
Now, we can solve for C by dividing both sides by 1.66:
\[ C = \frac{74700}{1.66} \]
Calculating this gives:
\[ C \approx 45000 \]

### Conclusion
The salary of C is Rs. 45,000.