Suman and Harpreet has some money in the ratio `5:2` Suman has Rs 300 .If Harpreet's money consists of only Rs 5 coins , how many coins did Harpreet have ?

Options

A. 60
B. 32
C. 24
D. 18

Answer

To solve the problem step by step, we can follow these instructions:

### Step 1: Understand the ratio of money between Suman and Harpreet.
Suman and Harpreet have money in the ratio of 5:2. This means that for every 5 parts Suman has, Harpreet has 2 parts.

### Step 2: Define the amounts in terms of a variable.
Let the common factor be \( k \). Then:
- Suman's money = \( 5k \)
- Harpreet's money = \( 2k \)

### Step 3: Use the information given about Suman's money.
According to the problem, Suman has Rs 300. Therefore, we can set up the equation:
\[ 5k = 300 \]

### Step 4: Solve for \( k \).
To find \( k \), divide both sides of the equation by 5:
\[ k = \frac{300}{5} \]
\[ k = 60 \]

### Step 5: Calculate Harpreet's money.
Now that we have \( k \), we can find out how much money Harpreet has:
\[ \text{Harpreet's money} = 2k = 2 \times 60 = 120 \]

### Step 6: Determine the number of Rs 5 coins Harpreet has.
Since Harpreet's total amount is Rs 120 and he only has Rs 5 coins, we can calculate the number of coins by dividing the total amount by the value of one coin:
\[ \text{Number of coins} = \frac{120}{5} = 24 \]

### Conclusion:
Harpreet has a total of 24 coins.