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A man fell into a manhole of depth 1 m ....

A man fell into a manhole of depth 1 m . If his mass is 65 kg , then what should be the work done by him to come out of it (Take g = `10 m s^(-2)`) .

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The correct Answer is:
650 J
m = 65 kg, g = 10 `ms^(-2)`
Work done to come out of the manhole = mgh
`= 65 xx 10 xx 1 = 650` J
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