Find the energy possessed by a bird of 5 kg moving at a constant height of 10 m from the ground with a speed of 2 m `s^(-1)`. (Take `g = 10 m s^(-2)`)

Answer

PE = 500 J, KE = 10 J

Explanation

Given, mass m = 5 kg
Height fro the ground, h = 10 m
Velocity, v = 2 `ms^(-1)`
g = 10 `ms^(-2)`
The bird possesses both potential energy (PE) and kinetic energy (KE).
PE = mgh
`= 5 xx 10 xx 10 = 500` J
`KE = (1)/(2) mv^(2) = (1)/(2) xx 5 xx 2^(2) = 10` J
Energy possessed by the bird = 500 + 10 = 510 J.