Home
Class 6
PHYSICS
A body is moved along the sides of a tri...

A body is moved along the sides of a triangle ABC once in anticlockwise direction by applying different forces along different sides as represented in the figure . The total displacement of the body and work done by the forces are `"______"` and "`_______"` respectively.

A

23 m, 26 J

B

15 m, 21 J

C

25 m, 32 J

D

0 m, 258 J

Text Solution

Verified by Experts

The correct Answer is:
D
Since the body is coming back to initial position A,
Total displacement of the body, s = 0
Total work done `(W) = W_(AB) + W_(BC) + W_(CA)`
`W = (6 xx 17) + (9 xx 4) + (8 xx 15) = 102 + 36 + 120 = 258` J
Hence, the correct option is (d).
Promotional Banner

Similar Questions

Explore conceptually related problems

A body moves from point A to point B under the action of a force varying in magnitude as shown in the force displacement graph. Find total work done by the force :

A body is moving along a circular path and 2012 revolutions round it. What is the total displacement of the body?

Assertion : Work done by the centripetal force in moving a body along a circle is always zero. Reason : Because displacement of the body is along the force.

A force acts perpendicular to the direction of motion of a body. What is work done?

When a body moves in a circular path, no work is done by the force since,

Whenever a force is applied on a body, work is done.

When the force applied and the displacement of the body are inclined at 90^(@) with each other, the work done is

Under the action of a force vec(F) = (3x) hat(i) N , a particle is moving in anticlockwise direction is a square loop of side 3m in x - y plane . What will be the total amount of work done ?