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A nut is placed in a nut cracker at 5 cm...

A nut is placed in a nut cracker at 5 cm from the fixed end. If the force experienced by the nut is 100 N when a force of 20 N is applied at the free end of the nut cracker, find the length of the nut cracker.

A

5

B

25

C

15

D

20

Text Solution

Verified by Experts

The correct Answer is:
B
Mechanical advantage `= ("Load")/("Effort ") = ("Effort arm ")/("Load arm ")`
Therefore `(100)/(20) = ("Effort arm ")/(5)` `rArr` Effort arm = 25 cm
Hence, the correct option is (b)
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