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The relative density of mercury is 13.6....

The relative density of mercury is 13.6. Find the ratio of the mass of mercury of a certain volume to that of water having ten times the volume of mercury.

Text Solution

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Let V `cm^3` be the volume of mercury.
` therefore ` Volume of water = 10 V `cm^3`
Density of mercury = 13.6 g `cm^(-3)`
` therefore ` Mass of mercury, `m_1` = (13.6) V g.
Density of water = 1 g `cm^(-3)`
` therefore ` Mass of water, `m_2 = (10 V) (1) g = 10 V g`.
Required ratio is `m_1, m_2 = 13.6 V`
10 V = 34 : 25 or 1.36:1
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Knowledge Check

  • The relative density of mercury is 13.66 . Its density in SI unit is:

    A
    `13.6(kg)/(m^3)`
    B
    `136(kg)/(m^3)`
    C
    `1360(kg)/(m^3)`
    D
    `13.6xx10^3(kg)/(m^3)`.

  • Water rises to a height of 10 cm in capillary tube and mercury falls to a depth of 3.112 cm in the same capillary tube. If the density of mercury is 13.6 and the angle of contact for mercury is 135^(@) , the ratio of surface tension of water and mercury is

    A
    `1:0.15`
    B
    `1:3`
    C
    `1:6`
    D
    `1.5 : 1`

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