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If the number of divisons on the vernier...

If the number of divisons on the vernier scale ofa standard vernier calliper is N, then N is always equal to (N- 1) main scale divisions. Would the vernier calliper be rendered useless if N is equal to fewer number of main scale divisions, for example N = ( N-3) M.S.D.? Why? How would the least count calculations be modified?

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What is least count? Should the value of least count be large or small? Will the accuracy of the vernier calipers be increased by decreasing the value of the least count?
`LC = (1MSD)/(N) = 1MSD - 1 VSD `
Given the principle of vernier is N V.S.D. = (N-1)M.S.D.
This implies that, `1VSD = ((N - 1)/(N)) MSD`
On substituting (2) in (1), find the value of L.C.
Consider, if N V.S.D. = (N-3) M.S.D.
` rArr ` 1 V.S.D. ` = ((N - 3)/(N))` MSD
Substituting (3) in (1), find the value of L.C. In which case is the L.C. is the least?
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