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In a vernier callipers 15 vernier scale ...

In a vernier callipers 15 vernier scale divisions correspond to 14 main scale divisions and one main scale division is equal to 1.5 mm. . An object is held between the external jaw of the given vernier caliipers. If the zeroth division of the vernier scale is to the left of the 20^(th) divison of the main scale, find the measurement of the object, if the 14th division of the vernier scale coincides with the main scale division.

Text Solution

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Given, 1 M.S.D. = 1.5 mm Number of V.S.D.s = 15 `rArr` N = 15
L.C. of the vernier callipers,
`LC = (1MSD)/(N) = (1.5mm)/(15)`
` rArr LC = 0.1mm`
Given M.S.R. = 19 x 1.5 mm = 28.5 mm
Given vernier coincidence, V.C. = 14
Measurement of length of given object
= M.S.R. + V.C. x L.C. = 28.5 mm + 14 x 0.1 mm
= 28.5 mm + 1.4 mm
= 29.9 mm = 2.99 cm
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