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A ball of mass 100g moving at a speed of...

A ball of mass 100g moving at a speed of 12 m `s^(-1)` strikes another ball of mass 200 g at rest. After the collision both the balls move with a common velocity. Find the common velocity.

Text Solution

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Let the common velocity of the two balls be .v..
`ul(1st)" "ul("ball")" "ul(2nd)" "ul("ball")`
`m_(1) = 100 g" "m_2 = 200 g`
`u_(1) = 12 m s^(-1)" "u_2 = 0 m s^(-1)`
`v_(1) = v= ?" "v_2 = v= ?`
From law of conservation of momentum,
`m_(1)u_(1) + m_2 u_2 = m_(1) v_(1) + m_2 v_2`
`100 xx 12 + 0 = 100 xx v + 200 xx v`,
`1200 = 300 v implies v= (1200)/(300) = 4m s^(-1)`
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