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A vessel of 100 cm^(2) cross sectional a...

A vessel of `100 cm^(2)` cross sectional area contains water. The mass of water is 2 kg. Find the pressure acting on the bottom surface.

Text Solution

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Mass of water in the vessel = 2 kg
`therefore` Weight= mg= `2 kg xx 9.8 m s^(-2)` = 19.6 N.
`therefore` Pressure= `("weight")/("area")=(19.6N)/(1xx10^(-2)m^2)` =1960 N `m^-2` = 1960 Pa
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