Nagarjun sagar dam is filled water till a height of 127 metres. If the mass of water per cubic centimeter is one gram, then find the difference in pressures acting at the following two points.
(i) Point exactly at a depth half that of the dam.
(ii) Point at the bottom of the dam.

Explanation

Height/depth of dam = 127 metres.
Density (d)=`("Mass")/("Volume")=(1 "gram")/(1cm^3)=1g cm^(-3)` = 1000 kg `m^(-3)`
Depth of the point = 127 m
Pressure at a point `(p_b) =127xx10^3xx10`
`= 1270 xx 10^3` pascals.
Difference in pressures = `P_b-P_a=(1270-635)xx10^3`
`= 635 xx 10^3`Pa