A body weight 16 N in a liquid whose specific gravity is 6. Find the weight of the body in water if it weight 40 N in air.

Explanation

Let `W_1,W_2` and `W_3` be the weight of the body in air, water and liquid, respectively.
`W_3` =16 N `W_2` =x ( to be determined)
`W_1=40 N`
Specific gravity of the liquid = 6
`rArr(W_1-W_3)/(W_1-W_2)=6rArr (40-16)/(40-x)=6`
`rArr` x = 36 N. Thus, weight of the body in water is 36 N.