The density of ice is `901 kg m^(-3)`. What percentage of ice lies below water ? The density of sea water is `1011 kg m^(-3)`. What fraction of an iceberg can be seen by us if the ice berg has the same density as that of ice ?

Explanation

(i) Apply the law of floatation.
Weight of the floating body = weight of the displaced Liquid
This implies V.D=vd
The percentage of the ice lying below the water is `=v/Vxx100`
Apply the same concept for the iceberg floating in sea water.
The percentage of the iceberg lying above the
sea water is=`(100-v/Vxx100)`
(ii) 0.11