When a metallic sphere is released from the surface of water filled in a container of uniform area of cross section it is found to reach the bottom of the container in 2 s. If the density of the material of the sphere is `4.9 g cm^(-3)`, calculate the pressure exerted by the liquid at the bottom of the container. Assume that only gravitational force and up-thrust act on the body.

Explanation

`V_(o)xxd_(o)xxa=V_(10)xxd_1xxg-V_(o)xxd_1xxg`
`A=g(d_o-d_1)/d_o`
`S=ut+1/2 at^2`
p=hdg
15,2880 Pa