Home
Class 8
PHYSICS
A disc siren with certain number of hole...

A disc siren with certain number of holes rotates uniformly 270 times in one and half minute. The frequency of the note emitted is 48 Hz. If the velocity of sound in air is `336 m s^(-1)`, find its wavelength and number of holes on the disc.

Text Solution

Verified by Experts

`(i) lamda = (v)/(n)`
No. of holes = `("frequency ")/("No of ratation in one sec")` (ii) 16
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION AND SOUND

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (LEVEL-3)|17 Videos
  • WAVE MOTION AND SOUND

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (LEVEL-1)|45 Videos
  • STARS AND THE SOLAR SYSTEM

    PEARSON IIT JEE FOUNDATION|Exercise COMPETITION CORNER|37 Videos

Similar Questions

Explore conceptually related problems

A body is vibrating 7200 times in one minute. If the velocity of sound is 360 m/s, find the wavelength of the sound produced.

The disc of a siren has 100 holes and rotates at the rate of 1000 revolutions per mintue. Find the frequency and wavelength of the note emitted by the siren. (Velocity of sound in air = 350 m//s )

An air column enclosed in an open pipe is vibrating in its fundamental mode . The fundamental frequency is 30 Hz. If the velocity of sound air is 300 m s ^(-1) , find the length of the pipe and frequency of 3rd overtone .

The disc of siren has n holes and the frequency of its rotation is 300 rpm. It produces a notes of wavelength 2.4 m. If the velocity of sound in air is 360 m/s, then the value of n will be

A body is vibrating 7200 times in one minute. If the velocity of sound is 360 m/s, find (i) frequency of the vibration in Hz,

A pipe closed at one end has length 83 cm. The number of possible natural oscilations of air column whose frequencies lie below 1000 Hz are (take, velocity of sound in air 332 m/s)

The frequency of the sound emitted by the loudspeaker is 1020 Hz. Calculate the wavelength of the sound wave in air in cm where its velocity is 340 m/s.

A pipe of length 85 cm is closed one end. Find the number of possible natural oscillationsof air column in the pipe whose frequencies lie below 1250 Hz. The velocity of sound in air is 340 m/s.

PEARSON IIT JEE FOUNDATION-WAVE MOTION AND SOUND-CONCEPT APPLICATION (LEVEL-2)
  1. The distance between a compression and the next rarefaction of a sound...

    Text Solution

    |

  2. A disc siren with certain number of holes rotates uniformly 270 times ...

    Text Solution

    |

  3. Two astronauts go the surface of the moon and would speak to each othe...

    Text Solution

    |

  4. A wave of time period 10 ms travels with a velocity of 1.5 m s^(-1). I...

    Text Solution

    |

  5. A sound wave of frequency 660 Hz incidents normally on a perfectly ref...

    Text Solution

    |

  6. A sound wave of frequency 660 Hz incidents normally on a perfectly ref...

    Text Solution

    |

  7. If 500 sound waves are produced in one minute, then find the time take...

    Text Solution

    |

  8. Audible ranges of frequencies is 20 Hz to 20,000 Hz. Find the range of...

    Text Solution

    |

  9. A tuning fork is excited first in air and then in water. In which case...

    Text Solution

    |

  10. A sound wave travelling in air is made to propagate through a liquid s...

    Text Solution

    |

  11. A sound wave travels 60m in the time taken to produce 50 waves. Find t...

    Text Solution

    |

  12. What would be the time period of a seconds pendulum constructed on the...

    Text Solution

    |

  13. If the percentage decrease in the length of a simple pendulum is 10%, ...

    Text Solution

    |

  14. The frequency of a sound wave is 200 Hz and its wavelength is 150 cm. ...

    Text Solution

    |

  15. The time period of a simple pendulum is given by T = 2pi sqrt((l)/(g))...

    Text Solution

    |

  16. The time period of a simple pendulum is given by T = 2pi sqrt((l)/(g))...

    Text Solution

    |

  17. The wavelength of a sound wave travelling in a solid becomes one third...

    Text Solution

    |

  18. The oscillation of a simple pendulum is graphically represented as fol...

    Text Solution

    |

  19. The oscillation of a simple pendulum is graphically represented as fol...

    Text Solution

    |

  20. The oscillation of a simple pendulum is graphically represented as fol...

    Text Solution

    |