The velocity of sound waves in a metal is found to `1400 ms^(-1)`. When they travel from metal to air its velocity changes to `340 ms^(-1)`. If the wavelength of sound waves in air is 200 m, find its wavelength in the metal

Explanation

`V_("met") = 1400 ms ^(-1) lamda_("met") = ?`
` V_("air") = 340 m s^(-1) lamda_("air") = 200 cm `
` V = n lamda `
`(V_("met"))/( V_("air")) = (lamda_("met"))/(lamda_("air"))=(1400 )/(340 ) = (lamda_("met"))/(200 )`
` implies lamda_("met") = 823.5 cm `