The heat capacity of 80 kg lead is found to be 11.2 kJ `K^(-1)`. Find its specific heat capacity

Explanation

The heat capacity is given by the relation `=mxxs`, where m is the mass of the substance, s is its specific heat capacity.
We are given that, m = 80 kg, and heat capacity `=11.2kJK^(-1)`
Substituting these values in the equation for heat capacity, we get `11200=80xxs`
`s=(11200)/(80)=140Jkg^(-1)K^(-1)`
`:.` The specific heat capacity of lead `=140Jkg^(-1)K^(-1)`