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Calcualte the mass of steam that should ...

Calcualte the mass of steam that should be passed though 60 g of water at `20^(@)C`, such that the final temperature is `40^(@)C`. (take specific latent heat of steam is 2250 J `g^(-1)`).

Text Solution

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Let mass of steam bem gm
Heat given out by steam to form water at `100^(@)C=mmxx2250Jg^(-1)`
Heat given out by water at `100^(@)C`
`=ms_(w)Deltatheta=mxx4.2xx(100-40)=252mJg^(-1)`
`=252mJg^(-1)`
Total heat given out `=2250m+252m`
`=2502mJg^(-1)`
Heat gained by water at `20^(@)C=60xx4.2xx(40-20)`
=5040J
`:.` Heat lost by a body = Heat gained by a body
2502 m = 5040
`m=(5040)/(2502)=2g`
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