A body at `20^(@)C` is in thermal equilibrium with a body at 293K.

Answer

To solve the problem, we need to determine if the two bodies are indeed in thermal equilibrium based on their temperatures.

### Step-by-Step Solution:

1. **Understand Thermal Equilibrium**:
- Thermal equilibrium occurs when two bodies are at the same temperature, and there is no heat exchange between them.

2. **Identify the Temperatures**:
- The first body is at a temperature of \(20^\circ C\).
- The second body is at a temperature of \(293K\).

3. **Convert Celsius to Kelvin**:
- To compare the temperatures, we need to convert the temperature of the first body from Celsius to Kelvin.
- The formula for conversion is:
\[ T(K) = T(°C) + 273 \]
- Applying this to \(20^\circ C\):
\[ T_1 = 20 + 273 = 293K \]

4. **Compare the Temperatures**:
- Now we have:
- Temperature of the first body \(T_1 = 293K\)
- Temperature of the second body \(T_2 = 293K\)
- Since \(T_1 = T_2\), both bodies are at the same temperature.

5. **Conclusion**:
- Since both bodies are at the same temperature of \(293K\), they are in thermal equilibrium. Therefore, there is no heat exchange occurring between them.

### Final Answer:
The body at \(20^\circ C\) is in thermal equilibrium with the body at \(293K\) because both temperatures are equal.