In one minute a total charge of 180C flows through a bulb when it is connected to a cell. Find the electric current flowing through the bulb.

Explanation

We know that electric current is defined as the rate of flow of charge in a circuit. It is given that the charge flowing through the bulb in 1 minute (= 60 s) is 180 C.
Therefore, the charge that flows in 1s = 180 C = 3 `Cs^(-1)` = 3A
We may use the formula , `I=(Q)/(t)` , where I is the electric current , Q is the charge that flows in t seconds.
Thus, `I=(180 C)/(60 S) =3 Cs^(-1) = 3a`
`:.` The electric current flowing in the blub = 3A.