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What is the work done to fits to lift a body of mass 5 kg to a height of 50 m from the ground (in J)? (g = 10 m `s^(-2)`)

A

250

B

`2.5xx10^(10)`

C

`2.5xx10^(3)`

D

`2.5xx10^(-4)`

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The correct Answer is:
To find the work done to lift a body of mass 5 kg to a height of 50 m, we can use the formula for gravitational potential energy, which is given by: \[ \text{Potential Energy (PE)} = m \cdot g \cdot h \] Where: - \( m \) = mass of the body (in kg) - \( g \) = acceleration due to gravity (in m/s²) - \( h \) = height (in m) ### Step-by-Step Solution: 1. **Identify the values**: - Mass (\( m \)) = 5 kg - Acceleration due to gravity (\( g \)) = 10 m/s² - Height (\( h \)) = 50 m 2. **Substitute the values into the formula**: \[ \text{PE} = m \cdot g \cdot h = 5 \, \text{kg} \cdot 10 \, \text{m/s}^2 \cdot 50 \, \text{m} \] 3. **Calculate the work done**: \[ \text{PE} = 5 \cdot 10 \cdot 50 = 2500 \, \text{J} \] 4. **Final answer**: The work done to lift the body is \( 2500 \, \text{J} \) or \( 2.5 \times 10^3 \, \text{J} \).

To find the work done to lift a body of mass 5 kg to a height of 50 m, we can use the formula for gravitational potential energy, which is given by: \[ \text{Potential Energy (PE)} = m \cdot g \cdot h \] Where: - \( m \) = mass of the body (in kg) - \( g \) = acceleration due to gravity (in m/s²) - \( h \) = height (in m) ...
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