Find the heat energy required to raise the temperature of 5 kg of water at `80^@C` to `100^@C`. (Specific heat of water is 1 cal `g^(-1)""^(@)C^(-1)` )

Calculate the amount of heat energy required to increase the temperature of 250 g of water from 27^(@)C to 67^(@)C (Specific heat capacity of water is 1 cal g^(-1@)C^(-1) )

Heat required to raise the temperature of one gram of water through 1^@C is

Heat required to increases the temperature of 1kg water by 20^(@)C

How much heat (in joule) is required to raise the temperature of 205 g of water from 21.2^(@)C to 91.4^(@)C . Specific heate of water is 4.18 J g^(-1) .^(@)C^(-1) Strategy : The specific heat of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1^(@C . Thus Specific heat = (("Amount of heat in joules"))/(("Mass of substance in grams")("Temperature change in" .^(@)C)) Rearrangement gives. Amount of heat (q) = Mass of substance (m) xx Specific heat (c ) xx Temperature change (Delta T)

How much heat energy is necessary to raise the temperature of 5 kg of water from 20 ^@ C " to " 100^@C ?