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A physiscs student performed an experime...

A physiscs student performed an experiment by taking a beaker with 1 l of water oat `30^(@)C` and dropping an iron sphere with temperature `90^(@)C` in it . After sometime student tmeasure their equailibrium temperature as `48^(@)C` .If the density of iron sphere is 7870 kg `m^(-3)` then find the volume of the iron sphere specifice heat of iron is 0.110 jcal `g^(-1@)C^(-1)`

Text Solution

Verified by Experts

Mass of 1 l of water =1 kg ,
`(Deltat)_w`=48-30 = `18^@C` ,
`(Deltat)_("iron")`=90-48=`42^@C`
Heat absorbed by water = Heat lost (removed ) from iron.
`(msDeltat)_w = (msDeltat)_"iron"`
`m_i=((msDeltat)_(W))/(sDeltat)_("iron")((1000xx1xx8)/(0.110xx42))`=3.896 kg
density= `"mass"/V`
`V=m/d=3.896/7870=4.95xx10^(-4) m^3`
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