Three persons `P_(1), P_(2)` and `P_(3)` are at different points A, B and C, respectively as shown in the figure. Two persons `P_(1)` and `P_(3)` clap at the same time. Which among the following can be the minimum distance between `P_(2)` and `P_(3)` to hear the clap sound distinctly by `P_(2)`? (Take the velocity of sound in air as `330 ms^(-1)`)

Options

A. 330 m
B. 384 m
C. 363 m
D. 660 m

Answer

C

Explanation

Velocity of sound `.v. = 330 m s^(-1)`
distance between `P_1 and P_2 = 330 m`
So, time taken to hear the sound
` t=( 330 )/(330 ) = 1s`
Human ear can hear two sounds separately only if they reach at interval of 1/10 of a second. So, the
time taken by the sound from `P_3` to reach `P_2` is minimum of `1 +(1)/(10) = 1.1 s.`
So, the distance between `P_2` and `P_3 = t xx v = 1.1 xx 330 = 363` m.