A person hears the sound of the explosion of a bomb after 5 s and another person hears the sound after 6 s. The ratio of minimum and maximum possible distance between the person is _____. ( velocity of sound in air is `330 ms^(-1)`)

Options

A. `1:1`
B. `1:2`
C. `1:11`
D. `5:6`

Answer

C

Explanation

Speed of Sound `= ("distance between the bomb and the person")/("Time interval")`
Minimum distance between them is equal to the distance travelled by the sound in 6 - 5 = 1 s
`d_1 = s xx t = 330 xx 1 =330 m`
The maximum distance between them is equal to the distance travelled by the sound in 6 + 5 = 11 s
` d_2= v xx t = 330 xx 11`
` d_1 : d_2 =(d_1)/(d_2)= (330 xx 1 )/(330 xx 11 )= (1)/(11) = 1:11 `