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Three boys Ravi, John and Asif stand in ...

Three boys Ravi, John and Asif stand in a straight line as shown in figure. Ravi and Asif fire crackers at the same instant of time. John hears the first sound after 2 s and the second sound after 2.5 s. Determine the distance between Ravi and Asif. The velocity of sound in air is `330 ms^(-1)`.

Text Solution

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Let the distance from Ravi to John be `d_1`, and the distance from Asif to John be `d_2`.
` V= (d_1)/(t_1)`
Let ` t_1 =2s`
` therefore d_1 = 2 xx 330 = 660 m`
Let ` t_2 = 2.5 s`
` therefore d_2= 2.5 xx 330 =825 m`
Total distance = 660 + 825 = 1485 m.
Thus, the distance between Ravi and Asif = 1485 m
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