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The escape velocity of the earth is 11.2...

The escape velocity of the earth is 11.2 km/s. For a planet whose mass and radius are twice those of the earth, the escape velocity will be

Text Solution

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` V_e = sqrt((2GM_e)/(R_e^(2))) = sqrt((2G(2M_e))/((2R_e)^(2)) )= sqrt( ( 2 xx GM_e)/(4R_e^(2)))`
` = sqrt((2)/(4)) xx sqrt((2GM_e)/(R_e^(2)))`
` = (1)/(V_2) (V_e ` on Earth )
` = 11 .27 xx 0.707 `
`= 7.96 ms ^(-1)`
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