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The weight of a body on the surface of m...

The weight of a body on the surface of moon is 1/6th of that on the Earth's surface. It is because acceleration due to gravit on the surface of moon is six times that on the surface of the Earth.

A

` 1 : 1`

B

` 1 : 6`

C

` 6 : 1`

D

` 1 : 2`

Text Solution

Verified by Experts

The correct Answer is:
B
Weight of A = `m_A xx g_e`
weight of B = `m_B xx g_m`
Where `g_e and g_m` are the acceleration due to gravity on the surface of the earth and on the surface of the moon, respectively.
` g_m = (g_e)/(6)`
` m_Ag_e = m_B g_m`
` m_A g_e =m_e xx (g_e)/(6)`
`m_A = (m_B)/(6),(m_A)/(m_B) = (1)/(6) = 1: 6`
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