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(a^(4)-a^(2)) div (a^(3) + a^(2)) =...

`(a^(4)-a^(2)) div (a^(3) + a^(2))` = ______

A

`(a^(2) +1)`

B

`a-1`

C

`a+1`

D

`a^(2)-1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((a^4 - a^2) \div (a^3 + a^2)\), we will follow these steps: ### Step 1: Rewrite the expression We start by rewriting the expression in fraction form: \[ \frac{a^4 - a^2}{a^3 + a^2} \] ### Step 2: Factor the numerator Next, we factor the numerator \(a^4 - a^2\). We notice that \(a^2\) is a common factor: \[ a^4 - a^2 = a^2(a^2 - 1) \] ### Step 3: Factor the denominator Now, we factor the denominator \(a^3 + a^2\). Here, \(a^2\) is also a common factor: \[ a^3 + a^2 = a^2(a + 1) \] ### Step 4: Substitute the factored forms back into the expression Now we substitute the factored forms back into the expression: \[ \frac{a^2(a^2 - 1)}{a^2(a + 1)} \] ### Step 5: Cancel common factors We can now cancel the common factor \(a^2\) from the numerator and the denominator: \[ \frac{a^2 - 1}{a + 1} \] ### Step 6: Factor \(a^2 - 1\) The expression \(a^2 - 1\) can be factored further using the difference of squares: \[ a^2 - 1 = (a - 1)(a + 1) \] ### Step 7: Substitute back into the expression Substituting this back into our expression gives: \[ \frac{(a - 1)(a + 1)}{a + 1} \] ### Step 8: Cancel the common factor again We can cancel the common factor \(a + 1\): \[ a - 1 \] ### Final Answer Thus, the final answer is: \[ \boxed{a - 1} \] ---
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