Home
Class 7
MATHS
The ages of A and B are in the ratio 5:4...

The ages of A and B are in the ratio 5:4 and the difference of their ages is 10 years. Find the ratio of their ages 8 years before.

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • RATIO AND ITS APPLICATIONS

    PEARSON IIT JEE FOUNDATION|Exercise ASSESSMENT TESTS (TEST 2)|12 Videos

  • RATIO AND ITS APPLICATIONS

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (LEVEL 3)|30 Videos

  • NUMBER SYSTEM

    PEARSON IIT JEE FOUNDATION|Exercise ASSESSMENT TESTS|24 Videos

  • Set theory

    PEARSON IIT JEE FOUNDATION|Exercise ASSESSMENT TEST Test 2|12 Videos

Similar Questions

Explore conceptually related problems

The ages of A and B are in the ratio 6:5 and the sum of their ages is 44 years. What will be the ratio of their ages after 8 years? a. 7:6 b. 8:7 c. 9:8 d. 3:4

The age of A and B are in the ratio 8:3 , six years hence , their ages Will be in the ratio 9:4 . Find their ages

The ages of A and B are in the ratio 8 : 3 Six years hence their ages will be in the ratio 9 : 4 find the their present ages.

The ages of A and B are in the ratio 5 : 2 After 5 years their ages will be in the ratio 15 : 7 , The present age of A is

The present ages for Seeta and Geeta are in the ratio 3:4. The product of their ages (in years) is 48. Find the sum of their ages (in years).