Home
Class 7
MATHS
Solve (gamma +2)/( 3) + ( gamma +3)/(2) ...

Solve `(gamma +2)/( 3) + ( gamma +3)/(2) = gamma + 1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \(\frac{\gamma + 2}{3} + \frac{\gamma + 3}{2} = \gamma + 1\), we will follow these steps: ### Step 1: Find a common denominator The denominators in the equation are 3 and 2. The least common multiple (LCM) of 3 and 2 is 6. We will multiply each term by 6 to eliminate the denominators. \[ 6 \left(\frac{\gamma + 2}{3}\right) + 6 \left(\frac{\gamma + 3}{2}\right) = 6(\gamma + 1) \] ### Step 2: Simplify each term Now, we simplify each term: \[ 2(\gamma + 2) + 3(\gamma + 3) = 6(\gamma + 1) \] ### Step 3: Distribute Next, we distribute the terms: \[ 2\gamma + 4 + 3\gamma + 9 = 6\gamma + 6 \] ### Step 4: Combine like terms Now, we combine the like terms on the left side: \[ (2\gamma + 3\gamma) + (4 + 9) = 6\gamma + 6 \] This simplifies to: \[ 5\gamma + 13 = 6\gamma + 6 \] ### Step 5: Rearrange the equation Now, we will move all terms involving \(\gamma\) to one side and constant terms to the other side: \[ 5\gamma - 6\gamma = 6 - 13 \] ### Step 6: Simplify both sides This simplifies to: \[ -\gamma = -7 \] ### Step 7: Solve for \(\gamma\) Now, we can solve for \(\gamma\): \[ \gamma = 7 \] ### Final Answer Thus, the solution to the equation is: \[ \gamma = 7 \] ---
Promotional Banner

Similar Questions

Explore conceptually related problems

If roots of x ^(3)+2x ^(2) +1=0 are alpha, beta and gamma, then the value of (alpha beta )^(3)+ (beta gamma ) ^(3) + (alpha gamma )^(3), is:

If roots of x ^(3) +2x ^(2) +1=0 are alpha, beta and gamma, then the vlaue of (alpha beta)^(3) + (beta gamma )^(3) + (alpha gamma )^(3) , is :

Show that | (1,1,1), (alpha ^ 2, beta ^ 2, gamma ^ 2), (alpha ^ 3, beta ^ 3, gamma ^ 3) | = (alpha-beta) (beta-gamma) (gamma-alpha) (alphabeta + betagamma + gammaalpha) |

alpha , beta , gamma are the roots of the equation x^(3)-3x^(2)+6x+1=0 . Then the centroid of the triangle whose vertices are (alpha beta,1/(alpha beta)) , (beta gamma, 1/(beta gamma)) , (gamma alpha,1/(gamma alpha)) is