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Solve: 7y - 3 le 2y + 14, y in W....

Solve: `7y - 3 le 2y + 14`, `y in W`.

A

`0,1,2`

B

`1,2,3`

C

`0,1,2,3`

D

`1,2,3,4`

Text Solution

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The correct Answer is:
To solve the inequality \( 7y - 3 \leq 2y + 14 \) where \( y \) belongs to the set of whole numbers \( W \), we will follow these steps: ### Step 1: Rearranging the Inequality Start by moving all terms involving \( y \) to one side and constant terms to the other side. \[ 7y - 3 \leq 2y + 14 \] Subtract \( 2y \) from both sides: \[ 7y - 2y - 3 \leq 14 \] ### Step 2: Simplifying the Terms Now, simplify the left side: \[ 5y - 3 \leq 14 \] ### Step 3: Isolate the Variable Next, add 3 to both sides to isolate the term with \( y \): \[ 5y \leq 14 + 3 \] \[ 5y \leq 17 \] ### Step 4: Solve for \( y \) Now, divide both sides by 5 to solve for \( y \): \[ y \leq \frac{17}{5} \] ### Step 5: Convert to Decimal Convert \( \frac{17}{5} \) to a decimal for better understanding: \[ \frac{17}{5} = 3.4 \] ### Step 6: Identify Whole Number Solutions Since \( y \) must be a whole number (i.e., \( y \in W \)), we consider whole numbers less than or equal to 3.4. The whole numbers satisfying this condition are: \[ y = 0, 1, 2, 3 \] ### Final Solution Thus, the values of \( y \) that satisfy the inequality are: \[ \{0, 1, 2, 3\} \] ---
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