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The sum of the digits of a two-digit num...

The sum of the digits of a two-digit number is 11. if 9 is subtracted from the number, then the digits interchagne their places. Find the number. The following steps are involved in solving the above problem. Arrange them in sequential order
(A) Let the units digit be x. therefore , the tens digit is (11-x).
`therefore` The number is `10(11-x)+x=110-9x`.
(B) Given that `110-9x-9=9x+11rArrx=5`.
(C) Units digit is S and tens digit is 6 and the required number is 65.
(D) The number formed by interchanging the digits is `10x+(11-x)=9x+11`.

A

ADBC

B

ABDC

C

ABCD

D

BADC

Text Solution

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The correct Answer is:
A
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