CAPACITANCE OF PLATES WITH DIELECTRIC

A parallel plate air capacitor has capacitance C. Half of space between the plates is filled with dielectric of dielectric constant K as shown in figure . The new capacitance is C . Then

A parallel plate capacitor, with plate separation d and plate area A, has a capacitance of 5muF . Calculate the new capacitance if the plate separation is reduced to 0.75d and the capacitor is completely filled with dielectric of dielectric constant 8.

A parallel plate capacitor with air between the plates has a capacitance C. If the distance between the plates is doubled and the space between the plates is filled with a dielectric of dielectric constant 6, then the capacitance will become.

A parallel plate capacitor with air between the plates has a capacitance C. If the distance between the plates is doubled and the space between the plates is filled with a dielectric of dielectric constant 6, then the capacitance will become.

A dielectric is placed in between the two parallel plates of a capacitor is shown in figure. The dielectric constant of the dielectric is K. If the initial capacitance is C, then the modified capacitance will be

Find the capacitances of the capacitance of the capacitors shown In figure .The plate area is A and the separation between the plate is d . Different dielectric slabe in a particular part of the figure area of the same thickness and the entire gap between the plate is filled with the dielectric slabs.

Find the capacitances of the capacitance shown In figure .The plate area is A and the separation between the plate is d . Different dielectric slabe in a particular part of the figure area of the same thickness and the entire gap between the plate is filled with the dielectric slabs.

Find the capacitances of the capacitance of the capacitors shown In figure .The plate area is A and the separation between the plate is d . Different dielectric slabe in a particular part of the figure area of the same thickness and the entire gap between the plate is filled with the dielectric slabs.