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If a = 2b and b = 4c, then root3(a^2/(16...

If a = 2b and b = 4c, then `root3(a^2/(16bc))=………..`

A

1

B

2

C

3

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we start with the given equations and substitute accordingly. ### Step 1: Understand the relationships We are given: - \( a = 2b \) - \( b = 4c \) ### Step 2: Substitute \( b \) in terms of \( c \) into \( a \) From the second equation, we can substitute \( b \) into the first equation: \[ b = 4c \implies a = 2(4c) = 8c \] So, we have: \[ a = 8c \] ### Step 3: Substitute \( a \) and \( b \) into the expression We need to evaluate: \[ \sqrt[3]{\frac{a^2}{16bc}} \] Substituting \( a \) and \( b \): \[ \sqrt[3]{\frac{(8c)^2}{16(4c)(c)}} \] ### Step 4: Simplify \( a^2 \) Calculating \( a^2 \): \[ (8c)^2 = 64c^2 \] Now substitute this back into the expression: \[ \sqrt[3]{\frac{64c^2}{16(4c^2)}} \] ### Step 5: Simplify the denominator Calculating the denominator: \[ 16(4c^2) = 64c^2 \] Now the expression becomes: \[ \sqrt[3]{\frac{64c^2}{64c^2}} = \sqrt[3]{1} \] ### Step 6: Calculate the cube root The cube root of 1 is: \[ \sqrt[3]{1} = 1 \] ### Final Answer Thus, the value of \(\sqrt[3]{\frac{a^2}{16bc}}\) is: \[ \boxed{1} \] ---
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