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In this formula In =[a+ (n-1) d] , mak...

In this formula ` I_n =[a+ (n-1) d] ,` make 'n' as the subject

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To make 'n' the subject of the formula \( I_n = a + (n - 1) d \), we will follow these steps: ### Step 1: Start with the original formula The original formula is: \[ I_n = a + (n - 1) d \] ### Step 2: Isolate the term containing 'n' To isolate the term containing 'n', subtract 'a' from both sides: \[ I_n - a = (n - 1) d \] ### Step 3: Divide both sides by 'd' Next, divide both sides by 'd' to isolate \( n - 1 \): \[ \frac{I_n - a}{d} = n - 1 \] ### Step 4: Solve for 'n' Now, add 1 to both sides to solve for 'n': \[ n = \frac{I_n - a}{d} + 1 \] ### Final Result Thus, the formula for 'n' in terms of \( I_n \), \( a \), and \( d \) is: \[ n = \frac{I_n - a}{d} + 1 \] ---
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