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In S=pisqrt(r^(2)+h^(2)), make h as the ...

In `S=pisqrt(r^(2)+h^(2))`, make h as the subject of the formula.

A

` h= sqrt((S)/(pi r )-r^(2))`

B

` h = sqrt((S^(2))/(pi r ^(2)) +r^(2))`

C

` h = sqrt( (pi ^(2) r^(2))/(S^(2)) - r^(2))`

D

` h = sqrt((S^(2))/(pi ^(2)r^(2)) -r^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
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