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If n(X)= 4, n(Y)= 9, and the sets X and ...

If n(X)= 4, n(Y)= 9, and the sets X and Y are disjoint, then find `n(XuuY)`.

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To find the number of elements in the union of two disjoint sets \(X\) and \(Y\), we can follow these steps: ### Step 1: Identify the number of elements in each set We are given: - \(n(X) = 4\) (the number of elements in set \(X\)) - \(n(Y) = 9\) (the number of elements in set \(Y\)) ### Step 2: Understand the concept of disjoint sets Disjoint sets are sets that have no elements in common. This means: - \(n(X \cap Y) = 0\) (the number of elements in the intersection of sets \(X\) and \(Y\)) ### Step 3: Use the formula for the union of two sets The formula for the number of elements in the union of two sets is given by: \[ n(X \cup Y) = n(X) + n(Y) - n(X \cap Y) \] ### Step 4: Substitute the known values into the formula Substituting the values we have: \[ n(X \cup Y) = n(X) + n(Y) - n(X \cap Y) \] \[ n(X \cup Y) = 4 + 9 - 0 \] ### Step 5: Calculate the result Now, perform the addition: \[ n(X \cup Y) = 4 + 9 = 13 \] ### Final Answer Thus, the number of elements in the union of sets \(X\) and \(Y\) is: \[ n(X \cup Y) = 13 \] ---
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