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If n(A)=25+x, n(B) = 27 - x, and n(A uuB...

If n(A)=25+x, n(B) = 27 - x, and `n(A uuB)=46`, then n `(A nnB)=`

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To solve the problem, we will use the formula that relates the number of elements in the union and intersection of two sets. The formula is: \[ n(A \cup B) = n(A) + n(B) - n(A \cap B) \] Given: - \( n(A) = 25 + x \) - \( n(B) = 27 - x \) - \( n(A \cup B) = 46 \) We need to find \( n(A \cap B) \). ### Step-by-step Solution: 1. **Write the formula for the union of sets**: \[ n(A \cup B) = n(A) + n(B) - n(A \cap B) \] 2. **Substitute the known values into the formula**: \[ 46 = (25 + x) + (27 - x) - n(A \cap B) \] 3. **Simplify the equation**: - Combine like terms: \[ 46 = 25 + 27 + x - x - n(A \cap B) \] - The \( x \) and \( -x \) cancel each other out: \[ 46 = 52 - n(A \cap B) \] 4. **Rearrange the equation to isolate \( n(A \cap B) \)**: \[ n(A \cap B) = 52 - 46 \] 5. **Calculate \( n(A \cap B) \)**: \[ n(A \cap B) = 6 \] Thus, the number of elements in the intersection of sets A and B is \( n(A \cap B) = 6 \). ### Final Answer: \[ n(A \cap B) = 6 \]
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