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45% of the students of a class participa...

`45%` of the students of a class participated in Physics Olympaid and `65%` of the students of the class participated in Maths Olympiad. 4 students participated in neither of these two and 8 students participated in both. Find how many students
participated in at least one Olympiad?

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To solve the problem step by step, we will use the information provided to find the number of students who participated in at least one Olympiad. ### Step 1: Define the total number of students Let the total number of students in the class be \( x \). ### Step 2: Determine the number of students participating in each Olympiad - Students participating in Physics Olympiad = \( 45\% \) of \( x \) = \( \frac{45}{100}x = 0.45x \) - Students participating in Maths Olympiad = \( 65\% \) of \( x \) = \( \frac{65}{100}x = 0.65x \) ### Step 3: Identify the number of students participating in both Olympiads We are given that 8 students participated in both Olympiads. ### Step 4: Use the principle of inclusion-exclusion To find the total number of students participating in at least one Olympiad, we can use the formula: \[ \text{Total participating} = (\text{Physics}) + (\text{Maths}) - (\text{Both}) \] Substituting the values we have: \[ \text{Total participating} = 0.45x + 0.65x - 8 \] This simplifies to: \[ \text{Total participating} = (0.45 + 0.65)x - 8 = 1.1x - 8 \] ### Step 5: Account for students participating in neither Olympiad We know that 4 students participated in neither Olympiad. Therefore, the equation can be set up as: \[ x - (1.1x - 8) = 4 \] This simplifies to: \[ x - 1.1x + 8 = 4 \] \[ -0.1x + 8 = 4 \] ### Step 6: Solve for \( x \) Rearranging gives: \[ -0.1x = 4 - 8 \] \[ -0.1x = -4 \] Dividing both sides by -0.1: \[ x = \frac{-4}{-0.1} = 40 \] ### Step 7: Calculate the number of students participating in at least one Olympiad Now that we have \( x = 40 \), we can find the number of students who participated in at least one Olympiad: \[ \text{Total participating} = 1.1(40) - 8 = 44 - 8 = 36 \] ### Final Answer The number of students who participated in at least one Olympiad is **36**. ---
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