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If A and B are two non - empty equivalen...

If A and B are two non - empty equivalent sets, then a possible value of `n(AxxB)` is ___________.

A

1

B

2

C

6

D

3

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The correct Answer is:
To solve the problem, we need to determine the possible value of \( n(A \times B) \) given that \( A \) and \( B \) are two non-empty equivalent sets. ### Step-by-Step Solution: 1. **Understanding Equivalent Sets**: - Two sets \( A \) and \( B \) are said to be equivalent if they have the same number of elements. This means \( n(A) = n(B) \). 2. **Let the Number of Elements be \( x \)**: - Since \( A \) and \( B \) are equivalent and non-empty, we can denote the number of elements in both sets as \( x \). Thus, \( n(A) = n(B) = x \). 3. **Finding the Number of Elements in the Cartesian Product**: - The Cartesian product \( A \times B \) consists of all possible ordered pairs where the first element is from set \( A \) and the second element is from set \( B \). - The formula for the number of elements in the Cartesian product is given by: \[ n(A \times B) = n(A) \times n(B) = x \times x = x^2 \] 4. **Determining Possible Values of \( x^2 \)**: - Since \( A \) and \( B \) are non-empty sets, \( x \) must be at least 1 (i.e., \( x \geq 1 \)). - The possible values for \( x \) can be 1, 2, 3, etc. Therefore, the possible values for \( x^2 \) will be: - If \( x = 1 \), then \( x^2 = 1^2 = 1 \) - If \( x = 2 \), then \( x^2 = 2^2 = 4 \) - If \( x = 3 \), then \( x^2 = 3^2 = 9 \) - And so on. 5. **Conclusion**: - The possible values of \( n(A \times B) \) are perfect squares: \( 1, 4, 9, 16, \ldots \) - The question asks for a possible value, and since we are looking for at least one value, we can conclude that a possible value of \( n(A \times B) \) is \( 1 \). ### Final Answer: A possible value of \( n(A \times B) \) is **1**. ---
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  12. If A and B are two non - empty equivalent sets, then a possible value ...

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